10n^2+6n-4=0

Solution for 10n^2+6n-4=0 equation:

10n^2+6n-4=0

a = 10; b = 6; c = -4;
Δ = b2-4ac
Δ = 62-4·10·(-4)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-14}{2*10}=\frac{-20}{20}
=-1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+14}{2*10}=\frac{8}{20}
=2/5
$